16t^2-40t=70

Solution for 16t^2-40t=70 equation:

16t^2-40t=70

We move all terms to the left:

16t^2-40t-(70)=0

a = 16; b = -40; c = -70;
Δ = b2-4ac
Δ = -402-4·16·(-70)
Δ = 6080
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6080}=\sqrt{64*95}=\sqrt{64}*\sqrt{95}=8\sqrt{95}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-8\sqrt{95}}{2*16}=\frac{40-8\sqrt{95}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+8\sqrt{95}}{2*16}=\frac{40+8\sqrt{95}}{32}
$